(50x^3+20x^2+x)/10

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Solution for (50x^3+20x^2+x)/10 equation: 


x in (-oo:+oo)

(50*x^3+20*x^2+x)/10 = 0

50*x^3+20*x^2+x = 0

x*(50*x^2+20*x+1) = 0

50*x^2+20*x+1 = 0

DELTA = 20^2-(1*4*50)

DELTA = 200

DELTA > 0

x = (200^(1/2)-20)/(2*50) or x = (-200^(1/2)-20)/(2*50)

x = (10*2^(1/2)-20)/100 or x = (-10*2^(1/2)-20)/100

x*(x-((-10*2^(1/2)-20)/100))*(x-((10*2^(1/2)-20)/100)) = 0

(x*(x-((-10*2^(1/2)-20)/100))*(x-((10*2^(1/2)-20)/100)))/10 = 0

( x-((-10*2^(1/2)-20)/100) )

x-((-10*2^(1/2)-20)/100) = 0 // + (-10*2^(1/2)-20)/100

x = (-10*2^(1/2)-20)/100

( x-((10*2^(1/2)-20)/100) )

x-((10*2^(1/2)-20)/100) = 0 // + (10*2^(1/2)-20)/100

x = (10*2^(1/2)-20)/100

( x )

x = 0

x in { (-10*2^(1/2)-20)/100, (10*2^(1/2)-20)/100, 0 }

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